Car Sort level guide
Car Sort Level 268 Walkthrough
Car Sort Level 268 uses a compact 10-space loop, opens cyan and white first, and spends the upper-right 3-count source only after green or blue receivers are ready.
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How to Solve Car Sort Level 268 — Full Solution
- Tap the visible cyan and white top banks.
- Release top blue, center-left yellow, then center green.
- Tap the numbered source once after green has a receiver, reducing 3 to 2.
- Alternate center yellow, green, and orange while lower blue, orange, and purple reveal.
- Pause at 8/10 and let yellow and green enter.
- Use the next numbered dispatch after the blue top receiver opens.
- Finish the tall cyan and white rows, then the center yellow/green/orange rows.
- Complete lower blue and purple, release the final numbered pair, and let the road empty.
Colors in this level:
Purple, Cyan, White, Blue, Yellow, Green, Orange
Common Mistakes to Avoid
- Tapping the numbered source while occupancy already shows 8/10.
- Opening the lower purple stack before its receiver is visible.
Quick Tips for Car Sort Level 268 (quick clues)
- Wait whenever occupancy reaches 8/10.
- Dispatch the numbered pair into an open receiver.
Board notes 5 details
- Layout
- Three tall top banks, three center banks, and three lower banks surround a square road that begins at 2/10; a round numbered 3 source sits at upper right.
- Goal
- Complete the cyan/white top, yellow/green/orange center, and blue/purple lower groups while timing all numbered dispatches.
- Opening
- Tap visible cyan and white, then top blue and center-left yellow.
- Danger Zone
- A numbered dispatch at 8/10 leaves no room for another hidden four-car reveal.
- Mechanics
- Deep question-cover queues, variable-height banks, a 10-space road, and a numbered source that releases one pair per tap.
Frequently Asked Questions
When should the numbered source be tapped in Car Sort Level 268?
Only after its shown green or blue pair has an open receiver and the road has more than two free spaces.
Why pause at 8/10?
The next source or hidden stack releases at least one pair, so waiting prevents the compact loop from saturating.